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Prove that $\frac{1}{ 9} < \sqrt {66} - 8 < \frac{1}{ 8}.$


Tags: MVT, approximation, root, using-a-theorem, proof, a--a, t3, c3
This is a hard problem and requires giving students a few hints. I like it because it is not obvious that the MVT can be used to prove the inequality and because it gives students experience in thinking about upper and lower bounds.

James Epperson 1998-08-09